assuming your given forces are in first quadrant
Fx + 48 cos 60 = 0
Fy + 25 + 48 sin 60 = 0
|F| = sqrt (Fx^2 + Fy^2)
tan theta = Fy/Fx
An object in equilibrium has three forces exerted on it. A 25 N force acts at 90 from the x-axis and a 48 N force acts at 60. What are the magnitude and direction of the third force
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