Asked by john
An object acted on by three forces moves with constant velocity. One force acting on the object is in the positive x direction and has a positive magnitude of 6.7N; a second force has a magnitude of 4.6 N and points in the negative y direction. (1)"Find magnitude of the third force acting on the object.
(2) Find the direction of the third force acting on the object in terms of pheta=-----------degrees from the + x direction.
(2) Find the direction of the third force acting on the object in terms of pheta=-----------degrees from the + x direction.
Answers
Answered by
bobpursley
see above . Check my work.
Answered by
Anonymous
1.7
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