The relationship between pressure and volume depends upon whether the process is adiabatic, isothermal, or something else. In your case, there a lot of heat removal going on because the pressure drops while the volume decreases. Work is received doing the compression. You have a "something else" process.
A better description of the process is needed. For an estimate of the work received, multiply the average pressure (500*10^3 N/m^2) by the volume change (0.5*10^-3 m^3) . That would be 250 Joules
An ideal gas is squeezed slowly from state A (pressure-600 kPa, volume- 1 L) to B ( pressure-400kPa, volume- 0.5 L).
What is the work done or received by the gas?
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1 answer