First, let's find the force applied by the skater using Newton's second law of motion:
F = m * a
where F is the force applied, m is the mass of the block, and a is its acceleration.
F = (20 kg) * (1.4 m/s²) = 28 N
So the magnitude of the force applied to the block by the skater is 28 N.
an ice skater applies a horizontal force to a 20 kg block on frictionless, level ice causing the block to accelerate uniformly at 1.4 m/s^2 to the right. after the skater stops pushing the block it slides onto a region of ice that is covered with a thin layer of sand. the coefficient of kinetic friction between the block and the sand-covered ice is 0.28 calculate the magnitude of the force applied to the block by the skater
1 answer
1 answer