An ice cube at 0 degrees Celsius is placed in a pouch and dropped into 30.0g of water in a cup at 45 degrees Celsius. The ice cube melts and the resulting water warms up. The lowest temperature reached by the 30.0g of water in the cup was 20.0 degrees Celsius. What was the mass of the ice cube that was placed in the pouch?

Question

- Please help me, I don't even know where to start or if where I think I have to start is even correct. Thank you.

Answer 1

Why didn't you tell us where you THINK you should start?
Let y = mass ice cube
To melt ice cube at zero C it is y*heat fusion. Add that to in as this,
Then (y*heat fusion) + [y*specific heat H2O x (Tfinal-Tinitial)] + [(mass H2O in cup x specific heat H2O x (Tfina-Tinitial)] = 0 and solve for y.

Answer 2

Thank you. Is there an official formula for what you came up with or some sort of rearranged formula?