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!!best homework help ever!!
uhh ur best options are:
a}google it
b}post same question 2mmorow when there are more tutors on line people who can help with chemistry :)
mass water x specific heat water x (Tfinal-Tinitial).
How much heat did the ice gain?
mass ice x heat fusion.
The sum of those should be zero.
Q_lost = Q_gained
The heat lost by the water (Q_lost) can be calculated using the formula:
Q_lost = mass_water * specific_heat_water * (final_temperature - initial_temperature)
The specific heat capacity of water is approximately 4.18 J/g°C.
The heat gained by the ice cube (Q_gained) can be calculated using the formula:
Q_gained = mass_ice * heat_fusion_ice
The heat of fusion for ice is approximately 333.5 J/g.
Since we know the initial and final temperatures of the water, as well as the mass of the water, we can calculate the heat lost by the water. Then, we can rearrange the equation to solve for the mass of the ice cube (mass_ice).
Let's calculate it step by step:
1. Calculate the heat lost by the water:
Q_lost = mass_water * specific_heat_water * (final_temperature - initial_temperature)
mass_water = 30.0 g
specific_heat_water = 4.18 J/g°C
final_temperature = 19.5°C
initial_temperature = 45.0°C
Q_lost = 30.0 g * 4.18 J/g°C * (19.5°C - 45.0°C)
2. Calculate the heat gained by the ice cube:
Q_gained = mass_ice * heat_fusion_ice
heat_fusion_ice = 333.5 J/g
3. Set the heat lost to be equal to the heat gained:
mass_water * specific_heat_water * (final_temperature - initial_temperature) = mass_ice * heat_fusion_ice
Now we need to rearrange the equation to solve for mass_ice:
mass_ice = (mass_water * specific_heat_water * (final_temperature - initial_temperature)) / heat_fusion_ice
Simply plug in the known values and calculate:
mass_ice = (30.0 g * 4.18 J/g°C * (19.5°C - 45.0°C)) / 333.5 J/g
mass_ice ≈ 10.134 g
Therefore, the mass of the ice cube is approximately 10.134 grams.