An extension on a spring when 5g was hung was 0.56cm.If Hooke's law is obeyed, what is the extension cost by a load of 20g(live answer in cm

Answer 1

Assuming that the spring follows Hooke's law, we can use the formula:

F = kx

where F is the force applied, x is the extension, and k is the spring constant. We can rearrange this equation to solve for k:

k = F/x

where F = 5g and x = 0.56cm:

k = (5g)/(0.56cm) = 8.93 g/cm

Now we can use this value of k to find the extension caused by a load of 20g:

F = 20g
x = F/k = (20g)/(8.93 g/cm) = 2.24 cm

Therefore, the extension caused by a load of 20g is 2.24 cm.