An express subway train passes through an underground station. It enters at t = 0 with an initial velocity of 23.0 m/s and decelerates at a rate of 0.150 m/s2 as it goes through. The station in 210 m long.

Question

An express subway train passes through an underground station. It enters at t = 0 with an initial velocity of 23.0 m/s and decelerates at a rate of 0.150 m/s2 as it goes through. The station in 210 m long.
(a) How long is the nose of the train in the station?
  
(b) How fast is it going when the nose leaves the station?
 
(c) If the train is 130 m long, at what time t does the end of the train leave the station?
  
(d) What is the velocity of the end of the train as it leaves?
  
Additional Materials

Lydia · Answer

(a) use d=vi*t+0.5*a*t^2 manipulate the equation to solve for t 210 m = (23 m/s)t+0.5(0.150 m/s^2)*t^2 t = 9.41 s (b) v = d/t = 210 m/ 9.41 s = 22.3 m/s I'm still trying to figure out the rest...

Bladimir · Answer

3.60