An elevator's cable can handle a tension of 95,500N. Assuming the car has a mass of 2950 kg and it is carrying a full load of passengers whose combined mass is 3750 kg, what is the minimum time required for the elevator to rise 50.0 m from rest?

Answer 1

95500=m(g+a)
solve for a.

Now, you can use a to figure time up...
vf^2=2ad solve for vf, then vavg=vf/2, and time up=50/Vavg

However, in the real world, elevators do no have constant acceleration as they travel. The accelerate to a fixed set max velocity, then travel at that velocity. Think of the difficulty of a constantly accelerating elevator...such as stopping it at floor 100...