An elementary student kicks a ball straight into the air with a velocity of 16 feet/sec. If acceleration due to gravity is -32 ft/sec^2, how many seconds after it leaves his foot will it take the ball to reach its highest point? Assume the position at time t = 0 is 0 feet.

Answer 1

the height h is

h = 16t - 32t^2

as with any parabola, the vertex is at t = -b/2a = -16/-64 = 1/4 second

Answer 2

Are you sure that's how you would do that? Because its not one of my options. my options are 1.25, 6, 0.50 or cannot be determined.

Answer 3

h = 16t(1-2t)

The roots are 0 and 1/2. The vertex lies halfway between the roots, at t = 1/4.