An electric train moving at 20kmh accelerates to a speed of 30kmh in 20 seconds.find the distance travelled in metres during the period of acceleration

Answer 1

d = Vi t + (1/2) a t^2

Vi = 20 /3.6 = 5.56 m/s

V final = 30/3.6 = 8.33 m/s

oh well, I do not need the physics equation because
Vaverage = (1/2)(5.56+8.33)
= 6.94 m/s

6.94 m/s * 20 s = 139 meters

Answer 2

Can't solve

Answer 3

I need the solving of the question