Select the larger value of reduction potential, reverse it and change the sign. That will be Zn^2+ + 2e ==> Zn Eored = -0.76
Zn ==> Zn^2++ 2e Eo ox = 0.76v
Co^2+ + 2e ==> Co Eo red = -.28v
-----------------------------
Zn +Co^2+ ==>Zn2+ + Co is cell rxn.
Eocell = Eoox + Eored = +0.76 + (-0.28) = ? is cell voltage.
That anode is where oxidation occurs. Which of the two half cells I've written above is oxidation(loss of electrons)? The cathode of course is the other one.
An elctrochemical cell is made up of Zn&Co
with their standard reduction potential -0.76V,-0.28V respectively.
1. Select the anode&cathode?
2. Write down the cell reactions?
3. Compute the e.m.f of the cell?
1 answer
1 answer