We can use the concept of Hooke's Law to solve this problem.
Hooke's Law states that the extension of an elastic material is directly proportional to the force applied to it, as long as the force is within the elastic limit. This can be represented by the equation:
F = kx
where F is the force applied, x is the extension, and k is the spring constant of the elastic material.
In this problem, we know that the cord can be stretched to its elastic limit by a load of 2N. This means that the spring constant of the cord is:
k = F/x = 2N / 0.6cm = 3.33 N/cm
We also know that when a force of 0.5N is applied, the cord extends by 0.6cm. Using Hooke's Law, we can find the extension of the cord when a force of 2.5N is applied:
F = kx
2.5N = 3.33 N/cm * (x - 0.6cm)
Solving for x, we get:
x = 1.80 cm
Therefore, the length of the cord when the stretching force is 2.5N will be:
35cm + 1.80cm = 36.80cm
An elastic cord can be stretched to its elastic limit by a load of 2N.if a 35cm length of the cord is extended 0.6cm by a force of 0.5N what will be the length of the cord when the stretching force is 2.5N
1 answer
1 answer