We can use the formula for Hooke's law: stress = force/area = (spring constant) x (strain)
In this case, we are given that the cord can be stretched to its elastic limit by a load of 2n, which means that the strain at this point is:
strain = (change in length) / (original length) = 0.6 cm / 35 cm = 0.0171
We can use this to find the spring constant:
stress = (2 n) / (area) = (spring constant) x (0.0171)
spring constant = (2 n) / (area x 0.0171)
We are then asked to find the length of the cord when the stretching force is 2.5n. From Hooke's law, we know that:
stress = (spring constant) x (strain)
We can rearrange this to solve for the new change in length:
(change in length) = (spring constant) x (strain) x (new force)
(change in length) = [(2 n) / (area x 0.0171)] x (0.0171) x (2.5 n)
(change in length) = 2.941 cm
Finally, we can add this change in length to the original length of the cord to find the new length:
(new length) = (original length) + (change in length)
(new length) = 35 cm + 2.941 cm
(new length) = 37.941 cm
Therefore, the length of the cord when the stretching force is 2.5n will be 37.941 cm.
An elastic cord can be be stretched to its elastic limit by a load of 2n if a 35cm length of the cord is extended 0.6cm by a force of 0.5n what will be the length of the cord when the stretching for is 2.5n
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