K = 0.5N/0.0.6cm = 0.833 N/cm.
Length = 35 + 2N*1cm/0.833N = 37.40 cm.
Increasing the force above 2N do
not increase length further.
An elastic cord can be stretched to it's elastic limit by a load of 2n.if a 35cm length of the cord is extended 0.6cm by a force of 0.5n.what will be the length of the cord when the stretching force is2.5n
22 answers
the ans is 352.8cm
Henry is correct
It cannot be determined from the data given
Pls for the length, am not sure you calculated well
Pls i hope this answer is the correct one plz
It cannot be determined at all
What about the 2.5N
i dont understand how u got to that answer 37.40
pls amy show ur workings🥺🥺😞
anybody should snd d workings with d answer
it cannot be determined from the given data
8.33
Cannot be determined from the data given.
Cannot be determined from the data given.
Pls is dat the correct answer 🙏🙏🙏🙏
Cannot be determined with the give data.
Dumb
Already, the spring has reached it's elastic limit at 2N so increasing the stretching force to 2.5N will not yield any good result further. So I think the correct answer is that the length can not be determined
The answer is 2000000000000000000000000000000000000000000000000000000000000004000000000000000000000000000000000000003000000000000009999900/00000000000000984747473+4+483;32828+33+37373737337838228(23++373-37374-37374+3737373737373373773737374474747474747474743737382929291001012982733773737373382829191910101018272626268283849494949949484(44!448448848483883939392928283+37373737337377374849494949484747447473882822+2+2(2(2828387337737373737377338373737733733738389220020100191711+3-3+37377373373737373737. I hope you got the answer above.
Pls for the length,am not sure you calculated it well
It cannot be determined from the data given
1 answer