We can use the concept of proportionality of deformation to determine the length of the cord when the stretching force is 2.5N.
Let's assume that the initial length of the cord is L and the extension produced by a force of 0.5N is x. We can then define the elastic constant of the cord as k = (2N)/L, since this force value represents the elastic limit of the cord.
Using this information, we can write:
x/L = F/k
where F is the stretching force and k is the elastic constant.
We can rearrange this equation to solve for L:
L = x/(F/k) = (xk)/F
Substituting the given values, we get:
L = (0.6 cm)((2 N)/L)/(0.5 N)
L = 2.4 cm
Therefore, the initial length of the cord is 35 cm and it extends to 37.4 cm when stretched by a force of 2.5N.
An elastic cord can be stretched to it's elastic limit by a load of 2N . If a 35cm length of the cord is extended 0.6cm by a force of 0.5 n what will be the length of the cord when the stretching force is 2.5n
1 answer
1 answer