24000-8x=2100
2737.5 each year
An automobile purchased for 24000 is worth 2100 after 8 years. Assuming that the car's value depriciated steadily from year to year, what was it worth at the end of the third year?
2 answers
2400(1+i)^-8 = 2100
.
.
1+i = 1.01683
then 2400(1.01683)^-3 = $2282.78
.
.
1+i = 1.01683
then 2400(1.01683)^-3 = $2282.78