Asked by Nick
An automobile and train move together along
parallel paths at 31.6 m/s.
The automobile then undergoes a uniform
acceleration of −4 m/s2 because of a red light
and comes to rest. It remains at rest for 44 s,
then accelerates back to a speed of 31.6 m/s
at a rate of 2.22 m/s2.
How far behind the train is the automobile
when it reaches the speed of 31.6 m/s, as-
suming that the train speed has remained at
31.6 m/s?
Answer in units of m
parallel paths at 31.6 m/s.
The automobile then undergoes a uniform
acceleration of −4 m/s2 because of a red light
and comes to rest. It remains at rest for 44 s,
then accelerates back to a speed of 31.6 m/s
at a rate of 2.22 m/s2.
How far behind the train is the automobile
when it reaches the speed of 31.6 m/s, as-
suming that the train speed has remained at
31.6 m/s?
Answer in units of m
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