An arrow slows down from 43 m/s to 28 m/s as it passes through an apple. If the 493 g apple was originally at rest and sped up to 0.44 m/s, what is the mass of the arrow?

Answer 1

momentum is conserved

momentum lost by arrow = gain by apple

(43 - 28) m = .493 * .44

Answer 2

Given:
M1 = ?, V1 = 43 m/s.
M2 = 0.493kg, V2 = 0.
V3 = 28 m/s = Velocity of M1 after collision.
V4 = 0.44 m/s = Velocity of M2 after collision.

Momentum before = Momentum after:
M1*V1 + M2*V2 = M1*V3 + M2*V4.
M1*43 + 0.493*0 = M1*28 + 0.493*0.44,
43M1 - 28M1 = 0.217,,
M1 = ?.
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