An arrow is shot into the air with a speed of 40 m/s at an angle of 65 degrees.

Question

a. Calculate the air time of the arrow
b. Calculate the maximum height the arrow reaches.
c. Calculate the range of the arrow.

Answer 1

vertical component = 40 m/s * sin(65º) ... V

horizontal component = 40 m/s * cos(65º) ... H

a. flight time = 2 * V / g

b. max height = V^2 / g

c. range = H * 2 * V / g