An archer wishes to shoot an arrow at a target at eye level a distance of 45.0 m away. If the initial speed imparted to the arrow is 68.2 m/s, what angle should the arrow make with the horizontal as it is being shot?

Answer 1

Range = Vo^2*sin(2A)/g.

Range = 45 m.
Vo = 68.2 m/s.
g = 9.8 m/s^2.
Solve for angle A.