An arrow is shot at an angle such that it's horizontal velocity is 40 m/s and it's vertical velocity is 20 m/s. Find the horizontal distance the arrow will travel before hitting the ground

Answer 1

do vertical problem first to find time in the air which is twice the time going up
v = Vi - g t
0 at top = 20 - 9.8 t
t = 20/9.8

2 t = time in air = 40/9.8

Now how far horizontal at constant speed of 40?
40(40/9.8) = 1600/9.8
or about 160 meters