a. d = 0.5g*t^2 = 0.095 m.
4.9t^2 = 0.095
t^2 = 0.0194
Tf = 0.139 s. = Fall time or time in air.
b. Dx = Xo*Tf = 20.6
Xo * 0.139 = 20.6
Xo = 148 m/s.
An arrow is aimed horizontally, directly at a target 20.6 meters away. when the arrow is released, it lands 0.095 meters below the target point.
a) How long was the arrow in the air?
b) How fast was the arrow moving when it left the bow?
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