An archer shoots an arrow horizontally at a target 14 m away. The arrow is aimed directly at the center of the target, but it hits 52 cm lower.

Question

1-What was the initial speed of the arrow?

** is this the formula for finding t :
y=h-1/2(gt^2)= 00.52-1/2(9.8t^2)
t=0.3258 s
initial speed= 14/0.3258=43 m/s

is my calculation correct?

Answer 1

I didn't use calculator, but is done correctly.