An archer standing on a cliff 48m above the level field below shoots an arrow at an angle of 30° above the horizontal with a speed of 80m/s. How far from the base of the cliff will the arrow land?

Answer 1

calculate the horizontal and vertical components of the arrow's flight
... horiz ... 80 m/s * cos(30º)
... vert ... 80 m/s * sin(30º)

plug the vert into the free-fall (height) equation to find the flight time
... h = 1/2 g t^2 + [80 m/s * sin(30º)] t + 48
... find t when h=0 , arrow on the ground

distance from cliff is the flight time multiplied by the horizontal velocity

Answer 2

h=78.09