An aqueous solution is prepared by dissolving 1.08 g of human serum albumin, a protein obtained from blood plasma, in 50.0 mL of water. The solution has an osmotic pressure of 0.00770 atm at 298 K. What is the molar mass of the albumin?

Answer: 6.86 x 10^4 g/mol

2 answers

pi = MRT
Substitute and solve for M
Then M = mols/L and solve for mols.
Then mols = grams/molar mass. You have mols and grams, solve for molar mass.
W2=1.08 g
π=5.85 mm of Hg
1 atm=760 mm
So, 1 mm =0.00131 atm.
Therefore,5.85 mm =7.6635*10^-3 atm
T=298 k
Volume of solution=50 cm^3= 50/1000=0.05 L
Then apply the above values in the formula,
π=CRT then calculate the answer

Answer will be 68655 g/mol