h=gt²/2 => t=sqrt(2h/g) =sqrt(2•73/9.81) =3.86 s
v(y) = gt = 9.81•3.86 =37.87 m/s
v=sqrt{v(x)²+v(y)²} =sqrt{37.87²+40²}=55.08 m/s
p=mv=Pv/g =177•55.08/9.81 =993.85 kg•m/s
tan α =v(y)/v(x) =37.87/40 =0.947
α=arctan0.947 =43.43⁰
An animal-rescue plane flying due east at
40 m/s drops a bale of hay from an altitude of 73 m .
The acceleration due to gravity is
9.81 m/s.
If the bale of hay weighs 177 N , what is the
momentum of the bale the moment it strikes the ground?
part 2
At what angle of inclination will the bale strike? Answer between −180◦
and +180◦.
1 answer
1 answer