An animal-rescue plane flying due east at 33.0 m/s drops a bale of hay from an altitude of 58.0 m. If the bale of hay weighs 173 N, what is the momentum of the bale the moment it strikes the ground?
2 answers
21=tff
M*g = 173.
M = 173/g = 173/9.8 = 17.7kg = Mass of the hay.
V^2 = Vo^2 + 2g*h = 0 + 19.6*58 = 1137,
V = 33.7 m/s.
Momentum = M*V =
M = 173/g = 173/9.8 = 17.7kg = Mass of the hay.
V^2 = Vo^2 + 2g*h = 0 + 19.6*58 = 1137,
V = 33.7 m/s.
Momentum = M*V =
1 answer