Asked by Beth
An anhydrous metal chloride, MCln, (1.500 g) is dissolved in water and the solution reacts with silver nitrate, requiring 47.34cm^3 of 0.5000M solution, to precipitate all the chloride as silver chloride. Identify M.
Answers
Answered by
GK
(0.4734 dm^3)(0.5000 mol/dm^3) = ____moles Ag+
Moles Cl- = moles Ag+
Grams of Cl- = (35.453 g/mol)(moles Cl-)
Grams of metal, M, = 1500g - grams Cl-
From the grams of M and grams of Cl- find the % composition of the sample.
Find the % composition of some chlorides: FeCl2, FeCl3, CuCl2, CaCl2, etc. until you find the one that matches the % composition of your sample.
Moles Cl- = moles Ag+
Grams of Cl- = (35.453 g/mol)(moles Cl-)
Grams of metal, M, = 1500g - grams Cl-
From the grams of M and grams of Cl- find the % composition of the sample.
Find the % composition of some chlorides: FeCl2, FeCl3, CuCl2, CaCl2, etc. until you find the one that matches the % composition of your sample.
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