Question

An aluminum calorimetry cup [mc = 0.6 kg, cc = 0.22 kcal/(kgC)] is filled with water [mw = 2.4 kg, cw = 1 kcal/(kgC)]. It is at a temperature of 30C. A sample of an unknown substance with mass mm = 2.34 kg, originally at a temperature of 210C, is added. After a while, the temperature of the water is 35C. What is the specific heat of this material?

Answer 1

I guess both the cup and the water started at 30 C and ended at 35 C
so they went up 5 C

heat in = .6*.22*5+2.4*1*5 = 12.66 KCal

heat out = 2.34 * c * (210-30)
= 421 c KCal

heat in = heat out

12.66 = 421 c

c = 0.03

are you sure you added 2.34 kg of this stuff and not maybe 2.34 grams?