Question
In an adiabatic calorimetry experiment, 100 mL of 0.500 M HCl was added to 100 mL 0.500 M NaOH to produce 200 mL 0.25 M NaCl. A temperature increase of 3.38 °C was measured. Calculate the heat of reaction associated with this process at 25 °C from the data in Table 1, for one mole of reactant and for the reaction conditions used. Use this value to calculate the heat capacity of the system, Ctotal.
Answers
DrBob222
What's in Table I?
Erxn = mass x specific heat x dT.
If you assume density of the solution is the same as H2O you use 200 g for mass; otherwise if Table I contains the density use that to calculate mass of the 200 mL solution.
Probably Table 1 contains specific heat; use that or 4.184 J/g*C and calculate E/rxn = E/0.25 mol and convert that to E/1 mol.
Ctotal = E/T
Erxn = mass x specific heat x dT.
If you assume density of the solution is the same as H2O you use 200 g for mass; otherwise if Table I contains the density use that to calculate mass of the 200 mL solution.
Probably Table 1 contains specific heat; use that or 4.184 J/g*C and calculate E/rxn = E/0.25 mol and convert that to E/1 mol.
Ctotal = E/T