An aluminum block has a starting temp of 300c the block is placed into 200 mililiters of water which has a temp of 20c what heat transfer will occur

Answer 1

To calculate the heat transfer that will occur between the aluminum block and the water, we can use the formula:

Q = mcΔT

Where:
Q = heat transfer (in Joules)
m = mass (in grams)
c = specific heat capacity (in J/g °C)
ΔT = change in temperature (in °C)

First, we need to determine the mass of the aluminum block. Let's assume its mass is 100 grams.

Next, we need to determine the specific heat capacity of aluminum. The specific heat capacity of aluminum is approximately 0.897 J/g °C.

Now, we can calculate the heat transfer:

Q_aluminum = (mass_aluminum) * (specific heat capacity_aluminum) * (ΔT_aluminum)
Q_aluminum = 100 g * 0.897 J/g °C * (20 °C - 300 °C)
Q_aluminum = 100 g * 0.897 J/g °C * (-280 °C)
Q_aluminum ≈ -25,032 J (negative sign indicates heat loss)

Similarly, we can calculate the heat transfer from the water:

Q_water = (mass_water) * (specific heat capacity_water) * (ΔT_water)
Q_water = 200 g * 4.18 J/g °C * (20 °C - 300 °C)
Q_water = 200 g * 4.18 J/g °C * (-280 °C)
Q_water ≈ -234,560 J (negative sign indicates heat loss)

Therefore, the total heat transfer that will occur between the aluminum block and the water is:

Q_total = Q_aluminum + Q_water
Q_total = -25,032 J + -234,560 J
Q_total ≈ -259,592 J

The negative sign indicates that heat is being lost by both the aluminum block and the water during the process.