To calculate the heat transfer that will occur between the aluminum block and the water, we can use the formula:
q = mcΔT
Where:
q is the heat transfer
m is the mass of the substance (water in this case)
c is the specific heat capacity of the substance (water in this case)
ΔT is the change in temperature
First, we need to find the mass of the water. We know that the volume of the water is 200 milliliters. The density of water is 1 gram per milliliter. Therefore, the mass of the water can be calculated as:
mass = volume × density
mass = 200 ml × 1 g/ml
mass = 200 g
Next, we need to find the specific heat capacity of water. The specific heat capacity of water is 4.186 Joules per gram per degree Celsius (J/g°C).
Using the formula, we can find the heat transfer:
q = mcΔT
q = (200 g) × (4.186 J/g°C) × (300°C - 20°C)
q = (200 g) × (4.186 J/g°C) × (280°C)
q ≈ 234,152 J
Therefore, the heat transfer that will occur between the aluminum block and the water is approximately 234,152 Joules.
An aluminum block has a starting temperature of 300oC. The block is placed into 200 milliliters of water, which has a temperature of 20oC. What heat transfer will occur?
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