An alpha particle moving at a speed of 5.20x10^4 m/s enters a perpendicular magnetic field with a strength of 3.0 mT. The magnitude of the acceleration of the particle as it enters the magnetic field will be a.bcx10^d m/s^2 ?

Answer 1

a = q V B/m

You do the numbers.
q = 2 e
m = 4*(proton mass)