calculate the velocity:
Bqv=Force
and force= massalpha*v^2/r
bqv=massv^2/r
solve for v.
Q)1 : Alpha particles travel through a magnetic field of 0.360T and are deflected in an arc of 0.0820m. Assuming the alpha particle are perpendicular to the field, what is the energy of an individual alpha particle?
3 answers
do i use the value of q/m ratio??
and thank u =)
and thank u =)
Magnetic field B = 0.36 T
Deflected radius of an arc r = 0.082 m
Charge of alpha particle q = 2e = 3.20435 × 10^-19 C
Mass of alpha particle m = 6.64 × 10^−27 kg
Magnetic Force = Bqv
Centripetal Force = mv²/r
Bqv = mv²/r
v = Bqr/m
v = (0.36)( 3.20435 × 10^-19)( 0.082) / (6.64 × 10^−27)
v = 1.42458 × 10^6 m/s
Energy of alpha particle E = (1/2)mv²
E = (1/2)( 6.64 × 10−27)( 1.42458 × 106)²
E = 4.7296 × 10^−15 J
Energy of alpha particle is 4.7296 × 10^−15 J.
Deflected radius of an arc r = 0.082 m
Charge of alpha particle q = 2e = 3.20435 × 10^-19 C
Mass of alpha particle m = 6.64 × 10^−27 kg
Magnetic Force = Bqv
Centripetal Force = mv²/r
Bqv = mv²/r
v = Bqr/m
v = (0.36)( 3.20435 × 10^-19)( 0.082) / (6.64 × 10^−27)
v = 1.42458 × 10^6 m/s
Energy of alpha particle E = (1/2)mv²
E = (1/2)( 6.64 × 10−27)( 1.42458 × 106)²
E = 4.7296 × 10^−15 J
Energy of alpha particle is 4.7296 × 10^−15 J.
1 answer