An Alaskan rescue plane traveling 49 m/s drops a package of emergency rations from a height of 177 m to a stranded party of explorers. The acceleration of gravity is 9.8 m/s 2 . Where does the package strike the ground relative to the point directly below where it was released?

4 answers

It proceeds under the plane at the same horizontal velocity component as the plane so it hits right under the plane (turn when you drop a bomb)
so 49 m/s until it hits ground
Vertical problem
v = -g t
z = 177 -(1/2) g t^2
at ground 0 = 177 -(1/2) 9.81 t^2
so
t^2 = 177/4.9
solve for t
now horizontal problem for answer
goes at 49 m/s for t seconds from drop point
Ok now the next part is, What is the horizontal component of the velocity just before it hits?
don't worry i figured the first part out, I just need the second one
There is NO horizontal force on the object
Therefore it moved at the forwards speed of the plane until it hits ground.
We already used that fact.
Remember:
"..... now horizontal problem for answer
goes at 49 m/s for t seconds from drop point ......"