s = 1/2 at^2, so a = 2s/t^2
v = at = (2s/t^2)t = 2s/t = 73.3 m/s
An airplane travels 330 m down the runway before taking off. Assuming that it has constant acceleration, if it starts from rest and becomes airborne in 9.00 s, how fast (in m/s) is it moving at takeoff?
A 73.3 m/s
B 36.7 m/s
C 1490 m/s
D 660 m/s
2 answers
36.7