0.5a*1^2 = 1.11 m.
0.5a = 1.11,
a = 2.22 m/s^2,
V1 = at = 2.22 * 1 = 2.22 m/s. = Velocity after 1 sec.
V2 = Vo + at,
V2 = 2.22 + 2.22*1 = 4.44 m/s. = Velocity after 2 sec.
An airplane starts from rest at the end of a runway and
accelerates at a constant rate. In the first second, the airplane
travels 1.11 m. What is the speed of the airplane at the end of the
second second?
1 answer