An airplane passenger has 150 ml of air in his stomach just before the plane takes off from a sea level airport where the pressure is 1 atm. What volume will this air have at a cruising altitude where the pressure in the man’s stomach has equalized with the cabin pressure 75 kPa? Assume that the temperature of the air in his stomach remains constant at 37 ◦C.
2 answers
72
75kPa=75000Pa
1atm= 101325pa
P1V1 = P2V2
150ml*101325=75000V2
V2=202.65ml
=202ml
1atm= 101325pa
P1V1 = P2V2
150ml*101325=75000V2
V2=202.65ml
=202ml
1 answer