Average velocity * time = stopping distance
(Vo/2) * t = X = 1300
Also, you can write Vo = a* t for the deceleration time.
The time t can be eliminated from the two equations, resulting in
(Vo/2)(Vo/a) = X
Vo^2 = 2 a X
Solve for a
An airplane lands and starts down the runway at a southwest velocity of 41 m/s. What constant acceleration allows it to come to a stop in 1.3 km?
1 answer