Express the velocity of the air plane into x (east) and y (north) directions.
v = (0, -590) km/h
Do the same for 65 km/hour wind from south-west, therefore at 45° towards NE:
w = (65√2/2,65√2/2)
Now add the components of v and w to get the resultant velocity.
The direction of the velocity is the angle atan2(y,x) taking into account of the quadrants. It should be in the fourth quadrant.
The distance from the "intended" position is the magnitude of the vector
(v -w)*15/60
since the duration is 15 minutes, and the speeds are in km/hour.
An airplane is heading due south at a speed of 590km/h. If a wind begins blowing from the southwest at a speed of 65.0km/h (average).
Calculate magnitude of the plane's velocity, relative to the ground.
Calculate direction of the plane's velocity, relative to the ground.
Calculate how far from its intended position it will be after 15.0min if the pilot takes no corrective action.
2 answers
I don't understand what you mean by the commas v=(0,-590)?
1 answer