An airplane flies with a speed of 425 mph and a heading of 63°. If the heading of the wind is 24°and the speed of the wind is 31 mph, what is the heading of the plane and the ground speed?

Question

I've done a couple questions like this but still a little fuzzy on setting it up, any help would be greatly appreciated.

Answer 1

V = 425mi/h @ 63o + 31mi/h @ 24o

X = 425*cos63 + 31*cos24 = 221.3 mi/h.
Y = 425*sin63 + 31*sin24 = 391.3 mi/hr.

tanA = Y/X = 391.3/221.3 = 1.7681
A = 60.5o. = Direction of plane.

V = X/cosA = 221.3/cos60.5 = 431 mi/h =
Velocity of plane.