Asked by peggy
An air-track glider attached to a spring oscillates between the 3.00 cm mark and the 50.0 cm mark on the track. The glider completes 10.0 oscillations in 36.0 s. What is the period of the oscillations?
What is the frequency of the oscillations?
What is the angular frequency of the oscillations?
What is the amplitude?
What is the maximum speed of the glider?
What is the frequency of the oscillations?
What is the angular frequency of the oscillations?
What is the amplitude?
What is the maximum speed of the glider?
Answers
Answered by
Guru
T = time/oscillations = 36/10 = 3.6s
f = 1/T = 1/3.6 = .278
Angular f = 2Pi/T = 2Pi/3.6 = 1.74
X (amplitude) = total distance/2 = (50cm - 3cm)/2 = 23.5 cm or .235 m
T = (2PiX)/Vmax or Vmax = (2PiX)/T = (2Pi0.235)/3.6 = .410 m/s
f = 1/T = 1/3.6 = .278
Angular f = 2Pi/T = 2Pi/3.6 = 1.74
X (amplitude) = total distance/2 = (50cm - 3cm)/2 = 23.5 cm or .235 m
T = (2PiX)/Vmax or Vmax = (2PiX)/T = (2Pi0.235)/3.6 = .410 m/s
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