Asked by Dan

A 190 g air-track glider is attached to a spring. The glider is pushed in 9.8 cm and released. A student with a stopwatch finds that 14 oscillations take 18.5 sec.
What is the spring constant?

Answers

Answered by bobpursley
frequency=1/2pi *sqrt(k/mass)
and frequency is 1/period.
Answered by Helmeppo
frequency= oscillations/second

f=14osc/18.5sec=0.76Hz

T= 1/f

T= 2pi/w

1/0.76Hz=2pi/w

cross multiply

w=2pi*0.76= 4.775 rad/s


w=sqrt(k/m)

square both sides

w^2=k/m

w^2 * m = k

k = w^2 * m

you have "w" and you have mass. Plug them in and find the spring constant. Don't forget to convert the mass from grams to kilograms.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions