An aeroplane flies at an average speed of 950km/hr from town P(lat.40degreeS, long.29.5degreeW) due east to town Q and then due south to town R. If the distance from Q to R along their common longitude is 4,500km and the whole journey took 11 hours, calculate longitude of Q and latitude of R. NB: take radius of the earth =6,400km, pie =3.142
2 answers
47867967697=876
If the change in longitude is θ radians, the WE distance is 6400θ km.
Since time = distance/speed, then (assuming a constant speed),
(6400θ + 4500)/950 = 11
θ = 0.9297 = 53.3°
So, now you know how far East Q is from P.
As for QR, 4500 = 6400θ
so, again, find θ and convert to degrees. It is that far South of Q and P.
Since time = distance/speed, then (assuming a constant speed),
(6400θ + 4500)/950 = 11
θ = 0.9297 = 53.3°
So, now you know how far East Q is from P.
As for QR, 4500 = 6400θ
so, again, find θ and convert to degrees. It is that far South of Q and P.
2 answers