An aeroplane flies from a town p on(lat.40N,38E)to another town Q on (Lat.40N,22W).It later flies to a third town T on(Lat.28N,22W). Calculate the average speed at which the aeroplane will fly from P to T via Q, If the journey takes 12 hours. Take R to be 6400 and py to be 22/7.

Answer 1

Given
R=6400 km
arc=Rθ

The first leg is equi-latitude at 40N with a meridian difference of θx=(38-22)=16°
Distance travelled
=Rθx cos(40)
=6400*(16*π/180)cos(40)
=1369.09 km

The second leg is along a meridian with a latitude difference of
θy(40-28)=12°.
Distance travelled
=Rθy
=6400*(12*π/180)
= 1340.41 km

Total distance = 1369.09+1340.41
= 2709.50 km
Speed=total distance / total time
=2709.50/12
=225.79 km/h

Answer 2

Nice one