An accelerating voltage of 2.46 * 10^3 V is applied to an electron gun, producing a beam of electrons originally traveling horizontally north in vacuum toward the center of a viewing screen 34.0 cm away. What is the magnitude of the deflection on the screen caused by the vertical component of the Earth's magnetic field, taken as 20.0 µT down?

Question

thank you

Answer 1

Force=Bqv, so covert the accelerating voltge to velocity (by kinetic energy).

1/2 m v^2=Voltage*e

solve for v, then force=Bq*velocity

Now, having the deflecting force, find the time to the screen (time=.34/velocity) which is the time in the deflecting force, so finally,
deflection= 1/2 (force/masselectgron)t^2

check all that.

Answer 2

oh alright sir thank you!