Under the influence of g, the electron drops slightly on the way to the screen. Calculate by how much.
You need to first get the speed V of the electron (using the beam voltage) and, from that, the time it takes to reach the screen. Call that time t
t = 0.34 m/V
The gravitational deflection of the electron beam is (g/2)*t^2
An accelerating voltage of 2.46 * 10^3 V is applied to an electron gun, producing a beam of electrons originally traveling horizontally north in vacuum toward the center of a viewing screen 34.0 cm away.
What is the magnitude of the deflection on the screen caused by the Earth's gravitational field?
I am not getting what we have to find here...
thank you
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