An 8-inch by 8-inch square is folded along a diagonal creating a triangular region. This resulting triangular region is then folded so that the right angle vertex just meets the midpoint of the hypotenuse. What is the area of the resulting trapezoidal figure in square inches?

Answer 1

well, the diagonal has length 8√2

the altitude of the triangular region is thus half that, or 4√2

So, the trapezoid has bases 8√2 and 4√2 and altitude 2√2

The area is thus 6√2 * 2√2 = 24