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Ammonia and gaseious hydrogen chloride combine to form ammonium chloride.

NH3(g) + HCl(g) = NH4Cl(s) (balanced)

If 4.21 L of NH3(g) at 27 C and 1.02 atm is combined with 5.35 L of HCl at 26 C and 0.998 atm, what mass of NH4Cl will be produced? Which gas is the limiting reactant? Which gas is present in excess?

PLEASE HELP!

4 answers

Use PV = nRT (once for each gas) to determine moles. Since the reaction is a 1:1 reaction (1 mole NH3 to 1 mole HCl), the reactant with the smaller number of moles will be the limiting reagent and convert that number of moles to grams NH4Cl.
So HCL would be the limiting reactant, right? And NH3 is present in excess. So do I convert 0.218 mol HCl to grams of NH4Cl?

Thanks btw for helping me. :)
no
wery no.